A system of equations is show. Y=-1/2xX^2+y^2=20Which of the following ordered pairs are solutions of the system of equations?Select two correct ordered pairs. A. (8,-4)B. (-4,2)C. (0,0)D. (4,-2)E. (8,-4)

Explanation:
For the system of equations given below
[tex]\begin{gathered} y=-\frac{1}{2}x \\ x^2+y^2=20 \end{gathered}[/tex]If we are to solve, we will simply substitute y=-1/2x into the second equation, so that
[tex]\begin{gathered} x^2+(-\frac{1}{2}x)^2=20 \\ x^2+\frac{1}{4}x^2=20 \\ \frac{4x^2+1x^2}{4}=\frac{5}{4}x^2=20 \\ \text{cross multiply} \end{gathered}[/tex][tex]\begin{gathered} x^2=\frac{20\times4}{5} \\ x^2=16 \\ x=-4 \\ \text{and} \\ x=4 \end{gathered}[/tex]The next step will be to substitute x=4 and x=-4 into the equation to get the required values of y
When x=4
[tex]\begin{gathered} y=-\frac{1}{2}x \\ y=-\frac{1}{2}(4)=-2 \\ \text{Thus one of the pair is} \\ (4,-2) \end{gathered}[/tex]Also,
When x=-4
[tex]\begin{gathered} y=-\frac{1}{2}x \\ y=-\frac{1}{2}(-4) \\ y=2 \\ \text{Thus, the second pair is} \\ (-4,2) \end{gathered}[/tex]Hence, the answers are: Options B and D