we have the expression
[tex]\frac{5}{9-24t^{}},\frac{3t-2}{8t^2+5t-3}[/tex]simplify the first term
[tex]\frac{5}{9-24t^{}}=\frac{5}{3(3-8t)^{}}=-\frac{5}{3(8t-3)^{}}[/tex]simplify the second term
[tex]\frac{3t-2}{8t^2+5t-3}=\frac{3t-2}{8(t+1)(t-0.375)}=\frac{3t-2}{(t+1)(8t-3)}[/tex]the LCD is equal to
