Random variable X is binomially distributed with aprobability of success p = 0. 65. After 12 trials,

Question A
Recall
[tex]\begin{gathered} P=0.65 \\ n=12 \\ p\text{ \lparen success\rparen=0.65} \end{gathered}[/tex][tex]\begin{gathered} P(6)=\frac{12!}{(12-6)!6!}\times0.65^6\times0.35^{12-6} \\ \\ P(6)=\frac{12!}{(12-6)!6!}\times0.65^6\times0.35^6 \\ \\ P(6)=924\times0.65^6\times0.35^6 \\ \\ P(6)=0.1281 \\ \end{gathered}[/tex]The final answer
[tex]0.12810[/tex]