Use the compound interest formulas AP 1.SA=P)and Ape" to solve the problem given Round answers to the nearest contFind the accumulated value of an investment of $10,000 for 4 years at an interest rate of 5% of the money is a compounded semiannualy, b. compounded quarterly, c.compounded monthly, d. compounded continuouslyBEa. What is the accumulated value of the money is compound

Use the compound interest formulas AP 1SAPand Ape to solve the problem given Round answers to the nearest contFind the accumulated value of an investment of 100 class=

Respuesta :

The formula for interest compounded continuously is:

[tex]P_t(cont)=P_0\cdot e^{r\cdot t}.[/tex]

The formula for the compound in periods:

[tex]P_t(period)=P_0\cdot(1+\frac{r}{n})^{n\cdot t}\text{.}[/tex]

Where:

• P_t is the amount of money after t years,

,

• P_0 is the initial amount of money,

,

• r is the ratio in decimal form,

,

• n is the number of compounded periods per year,

,

• t is the number of years.

We must compute the amount of money of an investment with:

• P_0 = $10,000,

,

• r = 5% = 0.05,

,

• t = 4 years.

a) Compounded semiannually

We use the second formula with n = 2:

[tex]P_4(semi)=\text{ \$10,000 }\cdot(1+\frac{0.05}{2})^{2\cdot4}\cong\text{ \$12,184.}03.[/tex]

b) Compounded quarterly

We use the second formula with n = 4:

[tex]P_4(quart)=\text{ \$10,000 }\cdot(1+\frac{0.05}{4})^{4\cdot4}\cong\text{ \$12,198.90.}[/tex]

c) Compounded monthly

We use the second formula with n = 12:

[tex]P_4(monthly)=\text{ \$10,000 }\cdot(1+\frac{0.05}{12})^{12\cdot4}\cong\text{ \$12,}208.95.[/tex]

d) Compounded continuously

We use the first formula:

[tex]P_4(cont)=\text{ \$10,000 }\cdot e^{0.05\cdot4}=\text{ \$12,}214.03.[/tex]

Answer

a) Compounded semiannually: $12,184.03

b) Compounded quarterly: $12,198.90

c) Compounded monthly: $12,208.95

d) Compounded continuously: $12,214.03

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