hi Ms or Mr I'm kind of stuck here with this problem could you please help me with this?

x=13
[tex]\measuredangle PQR=150[/tex]Explanation
Step 1
Let
[tex]\begin{gathered} \measuredangle PQS=16 \\ \measuredangle SQR=9x+17 \\ \measuredangle PQR=12x-6 \\ \\ \end{gathered}[/tex]Step 2
by the graph
[tex]\measuredangle\text{PQS}+\measuredangle SQR=\measuredangle PQR[/tex]replace
[tex]\begin{gathered} 16+9x+17=12x-6 \\ \end{gathered}[/tex]Step 3
Finally, solve for x
[tex]\begin{gathered} 16+9x+17=12x-6 \\ 9x+33=12x-6 \\ 9x-12x=-6-33 \\ -3x=-39 \\ x=\frac{-39}{-3} \\ x=13 \end{gathered}[/tex]Step 4
to find
[tex]\begin{gathered} \measuredangle PQR=12x-6=12\cdot13-6=156-6=150 \\ \measuredangle PQR=150 \\ \end{gathered}[/tex]I hope this helps you