Question

The 2000 Belmont Stakes winner, Commendable, ran the horse race at anaverage speed of 15.98 m/s. If Commendable and jockey Pat Day had acombined mass of 550.0 kg, what was their KE as they crossed the finish line?

Answer 1

Given:

The combined mass is

$m=550.0\text{ kg}$

The speed is

$v=15.98\text{ m/s}$

Required: find the kinetic energy.

Explanation:

To find the kinetic energy we will use the formula that is given as

$K.E=\frac{1}{2}mv^2$

Here,

$m$

is the mass and

$v$

is the speed.

Plugging all the values in the above relation, we get

$\begin{gathered} K.E=\frac{1}{2}mv^2 \\ K.E=\frac{1}{2}\times550.0\text{ kg}\times(15.98\text{ m/s})^2 \\ K.E=0.5\times550.0\text{ kg}\times255.36\text{ }(\text{m/s}^)^2 \\ K.E=70224.11\text{ J} \end{gathered}$

Thus, the kinetic energy is 70224.11 J.