The 2000 Belmont Stakes winner, Commendable, ran the horse race at anaverage speed of 15.98 m/s. If Commendable and jockey Pat Day had acombined mass of 550.0 kg, what was their KE as they crossed the finish line?

Respuesta :

Given:

The combined mass is

[tex]m=550.0\text{ kg}[/tex]

The speed is

[tex]v=15.98\text{ m/s}[/tex]

Required: find the kinetic energy.

Explanation:

To find the kinetic energy we will use the formula that is given as

[tex]K.E=\frac{1}{2}mv^2[/tex]

Here,

[tex]m[/tex]

is the mass and

[tex]v[/tex]

is the speed.

Plugging all the values in the above relation, we get

[tex]\begin{gathered} K.E=\frac{1}{2}mv^2 \\ K.E=\frac{1}{2}\times550.0\text{ kg}\times(15.98\text{ m/s})^2 \\ K.E=0.5\times550.0\text{ kg}\times255.36\text{ }(\text{m/s}^)^2 \\ K.E=70224.11\text{ J} \end{gathered}[/tex]

Thus, the kinetic energy is 70224.11 J.

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