According to the binomial distribution of probability
[tex]P(k;n,p)=P(X=k)=(nbinomialk)p^k(1-p)^{n-k}[/tex]
In our case,
[tex]n=10,p=68\text{percent}=0.68[/tex]
Therefore,
[tex]P(k\ge5)=\sum ^{10}_{k=5}(10binomialk)(0.68)^k(1-0.68)^{10-k}[/tex]
Thus,
[tex]\Rightarrow P(k\ge5)=(10binomial5)(0.68)^5(0.32)^5+(10binomial6)(0.68)^6(0.32)^4+(10binomial7)(0.68)^7(0.32)^3+(10binomial8)(0.68)^8(0.32)^2+(10binomial9)(0.68)^9(0.32)^1+(10binomial10)(0.68)^{10}(0.32)^0[/tex]
After calculations, we reach the following result
[tex]\Rightarrow P(k\ge5)=0.9362\ldots[/tex]
Then, the probability of Denita winning a medal in at least 5 of the next 10 races is, approximately 93.63%. The close option is 100%