Given,
The expression is,
[tex]P(x)=x^3-7x^2+15x-9[/tex]
If x- 3 is the factor of the given polynomial function, then on substituting the value of x = 3 in the polynomial function, it become zero.
Thus subsituting the value of x in the polynomial,
[tex]\begin{gathered} P(3)=3^3-7\times3^2+15\times3-9 \\ =27-7\times9+45-9 \\ =27+45-63-9 \\ =72-72 \\ =0 \end{gathered}[/tex]
Here, the obtained value of polynomial is 0.
Hence, x-3 is a factor of the given polynomial.
Thus, option A(true) is correct.
