Respuesta :

We have to find the missing parts of the table for the function:

[tex]y=(\frac{1}{7})^x[/tex]

This will be done by replacing each x-value onto the function.

For x=-2

We obtain:

[tex]y=(\frac{1}{7})^{-2}=(\frac{7}{1})^2=7^2=49[/tex]

This means that for x=-2, the value of y is 49.

For x=0

As every number (except 0) elevated to 0 is 1, we have

[tex]y=(\frac{1}{7})^0=1[/tex]

This means that for x=0, the value of y is 1.

For x=2

[tex]y=(\frac{1}{7})^2=\frac{1^2}{7^2}=\frac{1}{49}[/tex]

This means that for x=2, the value of y is 1/49.

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