Answer : The car will traveled 28.2 miles in 47 minutes and 36 miles in 1 hour
A car traveled at a steady speed. It travels 1 1/2 miles in 2 1/2 minutes
Given that:
Distance traveled by the car = 1 1/2 miles
Time = 2 1/2 minutes
[tex]\begin{gathered} \text{Speed = }\frac{dis\tan ce}{\text{time}} \\ \text{First, convert the mixed fractions into improper fractions} \\ \text{Distance = 1}\frac{1}{2}\text{ miles} \\ =\text{ }\frac{2\text{ x 1 + 1}}{2} \\ =\text{ }\frac{3}{2}\text{ miles} \\ \text{Time = 2 }\frac{1}{2}\text{ minutes} \\ \text{Time = }\frac{2\text{ x 2 + 1}}{2} \\ \text{Time = }\frac{5}{2}\text{ minutes} \\ \text{Speed = }\frac{Dis\tan ce}{\text{time}} \\ \text{Speed = }\frac{3}{2}\text{ / }\frac{5}{2} \\ \text{Speed = }\frac{3}{2}\text{ x }\frac{2}{5} \\ \text{Speed = }\frac{6}{10} \\ \text{Speed = }\frac{3}{5}\text{ miles / minutes} \\ \text{How far it will travel in 47 minutes} \\ \text{ since, Distance = sp}eed\text{ x time} \\ speed\text{ = }\frac{3}{5},\text{ and time = 47 minutes} \\ \text{Distance = }\frac{3}{5}\text{ x 47} \\ \text{Distance = }\frac{3\text{ x 47}}{5} \\ \text{Distance = }\frac{141}{5} \\ \text{Distance = 28.2 miles} \\ \text{How far it travels in 1 hour} \\ 1\text{ hour = 60 mins} \\ \text{Distance = }\frac{3}{5}\text{ x 60} \\ \text{Distance =}\frac{180}{5} \\ \text{Distance = 36 miles} \end{gathered}[/tex]Hence, the car will traveled 28.2 miles in 47 minutes and 36 miles in 1 hour
