Question

2x-3>5 or 3x-1<8 solve it?

Answer 1

$(-\infty,3)\text{ }\cup(4,\infty)$

Explanation

Step 1

solve inequality 1

$\begin{gathered} 2x-3>5\text{ } \\ \text{add 3 in both sides} \\ 2x-3+3>5+3 \\ 2x>8 \\ \text{divide both sides by 2} \\ \frac{2x}{2}>\frac{8}{2} \\ x>4 \end{gathered}$

Step 2

Solve inequality 2

$\begin{gathered} 3x-1<8 \\ \text{add 1 in both sides} \\ 3x-1+1<8+1 \\ 3x<9 \\ \text{divide both sides by 3} \\ \frac{3x}{3}<\frac{9}{3} \\ x<3 \end{gathered}$

then the solution is

$\begin{gathered} x>4\text{ or x}<3 \\ In\text{ interval denotation} \\ (-\infty,3)\text{ }\cup(4,\infty) \end{gathered}$

I hope this helps you