Respuesta :

Explanation

We have the simultaneous equation

[tex]\begin{gathered} 6x-2y=30---equation\text{ 1} \\ -3x+3y=15---equation\text{ 2} \end{gathered}[/tex]

To check if (10,15) is a solution, we will have to substitute

x=10 and y=15

into both equations and check if it is true

So for equation 1

[tex]\begin{gathered} 6(10)-2(15)=30 \\ True \end{gathered}[/tex]

Next, for the second equation

[tex]\begin{gathered} -3(10)+3(15)=15 \\ True \end{gathered}[/tex]

Thus,

We can conclude that (10,15) is a solution

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