Given:
[tex]\frac{\sqrt[]{3-2x}}{\sqrt[]{4x}}=2[/tex]
To find: The value of x
Explanation:
Squaring on both sides, we get
[tex]\begin{gathered} (\frac{\sqrt[]{3-2x}}{\sqrt[]{4x}})^2=2^2 \\ \frac{3-2x}{4x}=4 \end{gathered}[/tex]
Solving we get,
[tex]\begin{gathered} 3-2x=16x \\ 16x+2x=3 \\ 18x=3 \\ x=\frac{3}{18} \\ x=\frac{1}{6} \end{gathered}[/tex]
Final answer: Option C
[tex]x=\frac{1}{6}[/tex]
