In the case of two similar triangles, all their corresponding sides have a constant ratio. Therefore, if x is the length of the missing side,
[tex]\frac{14}{21}=\frac{x}{18}[/tex]Solving for x
[tex]\begin{gathered} \Rightarrow x=\frac{18\cdot14}{21}=12 \\ \Rightarrow x=12 \end{gathered}[/tex]The length of the missing side is 12mm