Given
Time taken, t=5.88 sec
Initial velocity, u=5 m/s
Final velocity, v=15 m/s
To find
The rate of acceleration
Explanation
Let the acceleration be a.
By equation of kinematics
[tex]\begin{gathered} v=u+at \\ \Rightarrow15=5+5.88a \\ \Rightarrow a=\frac{10}{5.88}=1.70\text{ m/s}^2 \end{gathered}[/tex]Conclusion
The acceleration is
B.
[tex]1.70\text{ m/s}^2[/tex]