The distance between the charges is given as,
[tex]d=5\text{ m}[/tex]The value of the charges are given as,
[tex]\begin{gathered} q_1=0.001\text{ C} \\ q_2=0.002\text{ C} \end{gathered}[/tex]According to the Coulomb's Law, the force of repulsion between these charges is,
[tex]F=k\frac{q_1q_2}{d^2}[/tex]where k is the electrostatic constant.
The value of k is,
[tex]k=9\times10^9Nm^2C^{-2}[/tex]Substituting the known values,
[tex]\begin{gathered} F=9\times10^9\times\frac{0.001\times0.002}{5^2} \\ F=7.2\times10^2\text{ N} \\ F=720\text{ N} \end{gathered}[/tex]Thus, the repulsive force acting between the charges is 720 N.
