Question

please find amplitude period and phase shifty=sin(2x-pi/2)

Answer 1

For the sinusoidal function:

$y=A\sin (Bx+C)+D$

we have that:

A represents the amplitude

2pi/B represents the Period

C is the phase shift

D is the vertical shift.

In this case, we have the following equation:

$y=\sin (2x-\frac{\pi}{2})$

then, the amplitude is A = 1.

For the period, we have the following:

$\begin{gathered} B=2 \\ \Rightarrow\frac{2\pi}{B}=\frac{2\pi}{2}=\pi=\text{Period} \\ \end{gathered}$

thus, the period is pi.

Finally, notice that C = -pi/2, thus, the phase shift is -pi/2