Question

Ann went bowling and got a score of 210 on her first game. On her second game, her score was 280. What was the percent of increase in her score on the second game?

Answer 1

ANSWER

33.33%

EXPLANATION

We have that her score on the first game was 210 and on her second game it was 280.

To find the percent of increase, we have to first find the difference between her first and second scores, then divide that by her first score and multiply by 100 (per cent).

Therefore, we have that the percent of increase is:

$\begin{gathered} \frac{280-210}{210}\cdot100 \\ \frac{70}{210}\cdot100 \\ 33.33\text{ \%} \end{gathered}$

That is the percent of increase.