find an equation of the line containing the two given points.Express your answer in the indicated form. points (1,2) and (3,10):standard form

Respuesta :

Equation of the line

There are several forms to express the equation of a line.

The equation of the line in slope-intercept form is:

y=mx+b

Being m the slope and b the y-intercept.

The equation of a line passing through points (x1,y1) and (x2,y2) can be found as follows:

[tex]\displaystyle y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]

The standard form of a line is:

Ax + By = C

We are given two points (1,2) and (3,10). The point-point equation is adequate according to the data we are provided.

[tex]\begin{gathered} \displaystyle y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1) \\ \text{Substituting:} \\ \displaystyle y-2=\frac{10-2}{3-1}(x-1) \end{gathered}[/tex]

Operating:

[tex]\begin{gathered} y-2=\frac{8}{2}(x-1)=4(x-1) \\ \\ \text{Operating:} \\ y-2=4x-4 \end{gathered}[/tex]

Subtracting 4x and adding 2:

y - 4x = -4 + 2 = -2

Rearranging:

-4x + y = -2

This is the required equation in standard form

RELAXING NOICE
Relax