Answer: OPTION A
F(x) is given as
[tex]\begin{gathered} F(x)\text{ = }\sqrt[3]{x\text{ - 15}} \\ \text{Let f(x) = y} \\ y\text{ = }\sqrt[3]{x\text{ - 15}} \\ \text{put y = x and x = y} \\ x\text{ = }\sqrt[3]{y\text{ - 15}} \\ x=(^{}y-15)^{\frac{1}{3}} \\ \text{Take the cube of both sides} \\ x^3\text{ = (}\sqrt[3]{y\text{ - 15}})^3 \\ x^3\text{ = y - 15} \\ y=x^3+15^{}^{} \\ f^{-1}(x)=x^3\text{ + 15} \end{gathered}[/tex]