Question

a bar of gold has a mass of 12.4kg a volume of 3 cm^3?

Answer 1

We need to calculate the density of the bar of gold, using the following formula:

$\text{density}=\frac{mass}{volume}.$

The units of density must be in kg/m^3 or g/cm^3. We can do the conversion from kg to g. Remember that 1 kg equals 1000 g:

$12.4kg\cdot\frac{1000g}{1kg}=12400g\text{.}$

Now, we can apply the formula using the last data:

$\begin{gathered} density=\frac{12400g}{3cm^3} \\ \text{density}=4133.33\text{ }\frac{g}{cm^3} \end{gathered}$

Let's see how would be the density in kg/m^3, remembering that 1 m^3 equal 1000000 cm^3:

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