Question

A baseball field is a square with sides of length 90 feet. What is theshortest distance between first base and third base?

Answer 1

127.3 ft

Explanation

Step 1

Diagram

as the field is a square ,we know each angle is 90 °, hence, the triangle formed by , the first base, the third base and the second baseis a rigth triangleb

so, we can use the Pythagorean theorem,it states that the sum of the squares on the legs of a right triangle is equal to the square on the hypotenuse:

so

Let

$\begin{gathered} side1=\text{ side2= 90 ft} \\ hypotenuse=h \end{gathered}$

hence

$\begin{gathered} 90^2+90^2=h^2 \\ 8100+8100=h^2 \\ 16200=h^2 \\ h=\sqrt{16200} \\ h=127.279 \\ \end{gathered}$

therefore, the answer is

127.3 ft

I hope this helps you