Given:
The gravitational force between two objects is,
[tex]16\text{ units}[/tex]
The mass of object 1 was doubled.
The distance between the objects was tripled.
To find:
The new force of attraction between the two objects
Explanation:
The force of attraction between two objects at a distance 'r' is,
[tex]F=\frac{Gm_1m_2}{r^2}[/tex]
According to the question,
[tex]\frac{Gm_1m_2}{r^2}=16[/tex]
The new force of attraction is,
[tex]\begin{gathered} F^{\prime}=\frac{G\times2m_1\times m_2}{(3r)^2} \\ =\frac{2Gm_1m_2}{9r^2} \\ =\frac{2}{9}F \\ =\frac{2}{9}\times16\text{ units} \\ =\frac{32}{9}\text{ units} \end{gathered}[/tex]
Hence, the new force of attraction is 32/9 units.
