Question

Point Q' is the image of Q(-5, 1) under a translation by 6 units to the right and 2 units down.What are the coordinates of Q'?

Answer 1

Answer:

$Q^{\prime}(1,-1)$

Step-by-step explanation:

The general rule for a translation by 6 units to the right and 2 units down is:

$(x,y)\rightarrow(x+6,y-2)$

This way, we'll have that:

$Q(-5,1)\rightarrow Q^{\prime}(-5+6,1-2)\rightarrow Q^{\prime}(1,-1)$

We can conclude that:

$Q^{\prime}(1,-1)$