Question

find three consecutive natural numbers such that the difference of four times the third number and twice the first number is five times the second number
answer pls asap

Answer 1

consecutive numbers are 1 apart
they are
n,n+1,n+2

so the diffference of 4 times (n+2) and twice (n) is 5 times (n+1)

4(n+2)-2n=5(n+1)
expand/distribute
4n+8-2n=5n+5
2n+8=5n+5
minus 2n both sides
8=3n+5
minus 5 both sides
3=3n
divide by 3
1=n
n+1=2
n+2=3

the numbers are 1,2,3