Question

A road rises 6 m over a distance of 80 m. What is the gradient angle of the road?

Answer 1

Explanation

From the statement, we know that the road:

• rises Δy = 6 m,

,

• over a distance Δx = 80 m.

The slope of the road (m) and gradient angle (θ) are given by:

$m=\tan(θ)=\frac{\Delta y}{\Delta x}\Rightarrowθ=\tan^{-1}(\frac{\Delta y}{\Delta x})$

Replacing the data of the problem, we get:

$\theta=\tan^{-1}(\frac{6m}{80m})\cong4.289\degree.$Answer

The gradient angle of the road is approximately 4.289°.