Please assist me in how to go about solving this problem

The given function is,
[tex]f(x)=log_2x+1[/tex]The graph of the function will be plotted below
A vertical asymptote is a vertical line that guides the graph of the function but is not part of it.
Hence, the vertical asymptote is at
[tex]x=0[/tex]The domain of a function f(x) is the set of all values for which the function is defined.
Hence, the domain of the function is
[tex]\:\left(0,\:\infty \:\right)[/tex]The range of a function is the complete set of all possible resulting values of the dependent variable.
Hence, the range of the function is
[tex]\:\left(-\infty \:,\:\infty \:\right)[/tex]Let get the f(x), when x = 2
[tex]\begin{gathered} f(x)=log_2x+1 \\ \therefore f(2)=log_22+1 \\ Note:log_22=1 \\ \therefore f(2)=1+1=2 \\ \therefore f(2)=2 \end{gathered}[/tex]