What is the area watered by the sprinkler? I can’t figure it out.

We are asked to determine the area of a circular sector. To do that we will use the following formula:
[tex]A=\frac{r^2\theta}{2}[/tex]Where:
[tex]\begin{gathered} r=\text{ radius} \\ \theta=\text{ angle in radians} \end{gathered}[/tex]Now, we convert the angle of 85° to radians using the following conversion factor:
[tex]1\pi=180\text{degrees}[/tex]Now, we multiply by the conversion factor:
[tex]\theta=85\times\frac{\pi}{180}=\frac{17\pi}{36}[/tex]Now, we substitute in the formula for the area:
[tex]A=\frac{(5m)^2(\frac{17\pi}{36})^2}{2}[/tex]Substituting the value of pi for 3.14
[tex]A=\frac{(5m)^2(\frac{17(3.14)}{36})^2}{2}[/tex]Solving the operations:
[tex]A=18.5m^2[/tex]Therefore, the area is 18.5 square meters.