Respuesta :

Explanation:

The expression is given below as

[tex]\frac{sinx}{1-cosx}[/tex]

Hence,from the expression above,

[tex]\begin{gathered} denominator=1-cosx \\ numerator=sinx \\ sinx,cant\text{ be simplified} \\ 1-cosx,cant\text{ be simplified further} \end{gathered}[/tex]

Hence,

The first step is for us to rationalize the denominator by multiplying both the numerator and denominator by its conjugate

The conjugate is given below as

[tex]1+cosx[/tex]

By rationalizing the denominator, we will have

[tex]\begin{gathered} \frac{s\imaginaryI nx}{1-cosx}\times\frac{1+cosx}{1+cosx} \\ =\frac{sinx(1+cosx)}{(1-cosx)(1+cosx)} \end{gathered}[/tex]

Hence,

The final answer is

[tex]\frac{s\imaginaryI nx(1+cosx)}{(1-cosx)(1+cosx)}[/tex]

OPTION D is the correct answer

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