Question

Find the perimeter and area of a rectangular hayfield that is 2,010 feet long and 520 feet wide.

Answer 1

The perimeter of a rectangle is:

$P=2l+2w$

The area of a rectangle is:

$A=l\cdot w$

For the given rectangular hayfield:

l=2,010 ft

w= 520ft

Perimeter:

$\begin{gathered} P=2(2,010ft)+2(520ft) \\ P=4,020ft+1,040ft \\ P=5,060ft \end{gathered}$

Area:

$\begin{gathered} A=(2,010ft)(520ft) \\ A=1,045,200ft^2 \end{gathered}$Then, the rectangular hayfirld has a perimeter of 5,060 feet and a area of 1,045,200 squared feet