ANSWER:
Acceleration of the cyclist is 2.1 m/s^2
The acceleration of the cyclist is not higher, that of the car is higher (2.8 m/s^2)
STEP-BY-STEP EXPLANATION:
Given:
u1 = 0 m/s
v1 = 10.7 m/s
t1 = 5.1 sec
u2 = 0 m/s
v2 = 25 m/s
t2 = 9 sec
We can calculate the acceleration, using the following formula:
[tex]a=\frac{v-u}{t}[/tex]
Replacing
[tex]\begin{gathered} a_1=\frac{v_1-u_1}{t_1}=\frac{10.7-0}{5.1}=2.1m/s^2 \\ a_2=\frac{v_2-u_2}{t_2}=\frac{25-0}{9}=2.8m/s^2 \end{gathered}[/tex]
The acceleration of the cyclist is 2.1 m/s^2, it is not higher than the acceleration of the car, since it is equal to 2.8 m/s^2
