The given expression is,
[tex]y=6x^5-x+10[/tex]
We have the rule,
[tex]\frac{d}{dx}(x^n)=nx^{n-1}[/tex]
Differentiating with respect to x, we have,
[tex]\begin{gathered} \frac{dy}{dx}=\frac{d}{dx}(6x^5-x+4) \\ \text{ = 5}\times6(x^{5-1})-1 \\ \text{ =30x}^4-1 \end{gathered}[/tex]
The answer is
[tex]30x^4-1[/tex]
