Question

What equation models the line that goes through the point (12.3) and has a slope of

Answer 1

$D)y=-\frac{1}{3}x+7$

Explanation

when you know the slope and a passing point of the line you can use the slope-point equation:

$\begin{gathered} y-y_1=m(x-x_1) \\ where\text{ mis the slope} \\ (x_1,y_1)\text{ is point from the line} \end{gathered}$

then

Step 1

a)let

point(12,3)

slope=-1/3

replace and isolate y

$\begin{gathered} y-y_1=m(x-x_1) \\ y-3=-\frac{1}{3}(x-12_{}) \\ y-3=-\frac{1}{3}x+\frac{12}{3}) \\ y-3=-\frac{1}{3}x+4 \\ \text{add 3 in both sides} \\ y-3+3=-\frac{1}{3}x+4+3 \\ y=-\frac{1}{3}x+7 \end{gathered}$

therefore, the answer is

$D)y=-\frac{1}{3}x+7$

I hope this helps you