Given data
*The given mass of the train car is m = 2600 kg
*The initial speed of the train is u = 10 m/s
*The second mass of the train car is M = 2500 kg
*The initial speed of the second train car is v = 0 m/s
The formula for the final velocity of the two train cars is given as
[tex]mu+Mv=(m+M)V[/tex]Substitute the values in the above expression as
[tex]\begin{gathered} 2600\times10+2500\times0=(2600+2500)V \\ V=5.09\text{ m/s} \end{gathered}[/tex]Thus, the final velocity of the two train cars is V = 5.09 m/s