Question

help fill in the blanks on the second problem i have the answer already

Answer 1

Given equation is,

$g(x)=x^2+3x-10$

Then,

$\begin{gathered} g(f(x))=\lbrack f(x)\rbrack^2+3\lbrack f(x)\rbrack-10 \\ =(x+4)^2+3(x+4)-10 \\ =x^2+8x+16+3x+12-10 \\ =x^2+11x+18 \end{gathered}$

So in the first blank, it will be,

$=(x+4)^2+3(x+4)-10$

And in the second blank it will be,

$undefined$