Question

Find the area of a regular hexagon with the given measurement. 4-inch side A = sq. in. Please show work.

Answer 1

Answer:

The area of hexagon is 41.57  inch².

Step-by-step explanation:

The formula for area of regular hexagon is

$A=\frac{3\sqrt{3}}{4}a^2$

Where, a is the side length of regular hexagon.

It is given that the length of side is 4 inch.

The area of regular hexagon is

$A=\frac{3\sqrt{3}}{4}\times(4)^2$

$A=\frac{3\sqrt{3}}{2}\times 16$

$A=3\sqrt{3}\times 8$

$A=24\sqrt{3}$

$A=41.57$

Therefore the area of hexagon is 41.57  inch².

Answer 2

Answer:

$A=41.58(inches)^2$

Step-by-step explanation:

Given: The side of the regular hexagon measures 4 inches.

To find: The area of the regular hexagon.

Solution: The area of the regular hexagon can be found as:

$A=\frac{3\sqrt{3}}{2}(side)^2$

$A=\frac{3\sqrt{3}}{2}(4)^2$

$A=\frac{3\sqrt{3}}{2}(16)$

$A=24\sqrt{3}$

$A=41.58(inches)^2$

Thus, the area of the regular hexagon will be equal to $41.58 (inches)^2$.