According to the given data we have the following:
circle Center (4,-2)
tangent to the line x=1
To finde the standard form of the equation we would have to make the following:
According to the data the center is (h,k)=(4,-2)
using the following formula we can find the equation:
[tex](x-h)^2+(y-k)^2=r^2[/tex]Since the tangent line is x=1 and r=4-1=3
Therefore, the standard form of the equation of a circle
Center (4,-2) and tangent to the line x=1 would be the following:
[tex](x-4)^2+(y+2)^2=3^2[/tex]
