The diameter of the ball is 12 inches, but for the volume we need the radius (half of the diameter) according to the formula for the volume of a sphere:
[tex]\text{Volume}=\frac{4}{3}\pi\cdot R^3[/tex]Then in our case, the radius is 12/2 = 6 in
That we can replace in the formula as shown below
[tex]\text{Volume}=\frac{4}{3}\pi\cdot(6)^3=904.32[/tex]Since we need to round to the nearest tenth this valu, we type the following: 904.3 in^3
