Question

. There are 160 houses in a neighborhood. Company X provides electricity to of the houses. 1 8 2 1 5 Company Y provides electricity to of the houses. Company Z provides electricity to the remaining houses. In this neighborhood, Company Z provides electricity to: A. 20 houses B. 76 houses C. 64 houses D. 84 houses

Answer 1

Between the three companies, they have to provide the 100% of houses, that is, the fractions must add 1, so the company Z provides electricity to

$1-\frac{1}{8}-\frac{2}{5}=\frac{40}{40}-\frac{5}{40}-\frac{16}{40}=\frac{19}{40}$

19/40 of the houses. Since there are 160 houses, this means that the company Z provides energy to

$160\times\frac{19}{40}=76$

Then, the answer is B. 76 houses.