The figure shows a walkway around a swimming pool. The width of the walkway is 4 1/2 ft all the way aroundWhat is the area of the walkwayA 605 ft2B 1,251 ft2C 2'682 ft2B 3,675 ft2LAST QUESTION OF THE DAY HELP ME OUT!!!

First, we have to transform the mixed number into a fraction.
[tex]4\frac{1}{2}=\frac{4\cdot2+1}{2}=\frac{8+1}{2}=\frac{9}{2}[/tex]The width of the walkway is 9/2 feet.
Notice the length of the small rectangle is 30 feet. We have to sum 9/2 twice to 30 because the width of the walkway is on both sides like the image below shows.
The sum for the length of the walkway is
[tex]\frac{9}{2}+30+\frac{9}{2}=30+\frac{9+9}{2}=30+\frac{18}{2}=30+9=39[/tex]The length of the walkway is 39 feet.
The sum for the width is
[tex]\frac{9}{2}+100+\frac{9}{2}=100+\frac{9+9}{2}=100+\frac{18}{2}=100+9=109[/tex]The width of the walkway is 109 feet.
Now, to find the area we multiply the length and the width.
[tex]A=39\cdot109=4,251ft^2[/tex]However, we have to subtract the area of the smaller rectangle to find the actual area of the walkway.
[tex]A_{small}=100\cdot30=3000ft^2[/tex]Then,
[tex]A_{walk}=A-A_{small}=4,251-3000=1,251ft^2[/tex]