223.5K
According to general gas equation
[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]Given the following parameters
P1 = 1.0 atm (standard pressure)
V1 = 750mL
P2 = 2.0atm
V2 = 500mL
T2 = 25 + 273 = 298K
Substitute the given parameters
[tex]\begin{gathered} T_1=\frac{P_1V_1T_2}{P_2V_2} \\ T_1=\frac{1.0\times750\times298}{2.0\times500} \\ T_1=\frac{223500}{1000} \\ T_1=223.5K \end{gathered}[/tex]Hence the required initial temperature is 223.5K