Given that she bought a total of 10 items ( pants and t-shirts) each pair of pants cost $53, each shirt is $27. She spent $374, we have two linear equations as follows:
Let x be the number of pants and let y be the number of t-shirts, then:
[tex]53x+27y=374[/tex][tex]x+y=10[/tex]In order to find how many and shirts she bought, we have to solve this linear system of two equations and two variables:
[tex]53x+27y=374\rightarrow53x=374-27y\rightarrow x=\frac{374-27y}{53}[/tex][tex]\mathrm{Substitut}e\mathrm{\:}x=\frac{374-27y}{53}\text{ }into\text{ x + y = 10}[/tex][tex]\frac{374-27y}{53}+y=10[/tex][tex]\frac{374+26y}{53}=10[/tex][tex]\mathrm{Isolate}\:y[/tex][tex]\frac{53\left(374+26y\right)}{53}=10\cdot \:53[/tex][tex]374+26y=530[/tex][tex]374+26y-374=530-374\rightarrow26y=156\rightarrow y=6[/tex]then:
[tex]x=10-y=10-6=4[/tex]So, she bought 4 pants and 6 t-shirts.