Question
[tex]x^{\frac{-4}{5}}.x^{\frac{7}{8}}[/tex]Apply multiplication law of exponent.
[tex]\begin{gathered} \text{Multiplication law of exponent } \\ X^m.^{}X^{n\text{ }}=X^{m+n} \end{gathered}[/tex][tex]\begin{gathered} X^{\frac{-4}{5}\text{ }}.X^{\frac{7}{8}} \\ =X^{\frac{-4}{5}\text{ + }\frac{7}{8}} \\ =X^{\frac{-4\text{ x 8 + 5 x 7}}{40}} \\ =X^{\frac{-32\text{ + 35}}{40}} \\ =X^{\frac{3}{40}} \end{gathered}[/tex]