The distributive property says that
[tex]a(x+y)=ax+ay[/tex](1). Using the above fact, the expression 5(y -3) becomes
[tex]5(5-y)=5(5)-5(y)[/tex][tex]\rightarrow\textcolor{#FF7968}{25-5y.}[/tex](2).
[tex]-4(-2x+6)=-4(-2)x+6(-4)[/tex][tex]\textcolor{#FF7968}{8x-24}[/tex](3).
[tex]\frac{1}{2}(6a+10)=\frac{1}{2}(6a)+\frac{1}{2}(10)[/tex][tex]\rightarrow\textcolor{#FF7968}{3a+5.}[/tex]