Question

solve the system of linear equations by substitution y=3x-1 and y=x-7

Answer 1

We have the system of equations:

$\begin{gathered} y=3x-1 \\ y=x-7 \end{gathered}$

Since we have two equations that are equal to y, we can set them equal to each other.

$3x-1=x-7$

Lets add 1 to both sides of the equation.

$3x=x-6$

Subtract x from both sides of the equation.

$2x=-6$

Divide both sides of the equation by 2.

$x=-3$

Now, we can substitute x = -3 back into either equation in order to find its corresponding y-value.

$y=3(-3)-1$

Simplify this equation...

$\begin{gathered} y=-9-1 \\ y=-10 \end{gathered}$

The solution to this system of linear equations is (-3, -10).