Given that:
- The initial value of the car was $23995.
- Its value linearly depreciated to $9300 over 10 years.
- The variable "y" represents the value of Zac's car (in dollars) and "x" represents the number of years since it’s purchased.
You need to remember the Slope-Intercept Form of the equation of a line:
[tex]y=mx+b[/tex]Where "m" is the slope of the line and "b" is the y-intercept.
In this case, the value of "b" is the initial value of the car when it was purchased by Zac:
[tex]b=23995[/tex]By analyzing the data given in the exercise, you can identify this point:
[tex](10,9300)[/tex]Where:
[tex]\begin{gathered} x=10 \\ y=9300 \end{gathered}[/tex]Therefore, you can substitute all the known values into the following equation and solve for the slope "m":
[tex]y=mx+b[/tex]Then, you get:
[tex]\begin{gathered} 9300=m(10)+23995 \\ \\ 9300-23995=10m \end{gathered}[/tex][tex]\begin{gathered} -14695=10m \\ \\ \frac{-14695}{10}=m \\ \\ m=-1469.5 \end{gathered}[/tex]Knowing "m" and "b", you can set up the following equation to represent this situation:
[tex]y=-1469.5x+23995[/tex]Hence, the answer is:
[tex]y=-1469.5x+23995[/tex]