[tex]\begin{gathered} \text{Given:} \\ 2-6x=n^2-1 \end{gathered}[/tex][tex]\begin{gathered} \text{Subtract }2\text{ from both sides to get rid of }2\text{ on the right side} \\ 2-6x=n^2-1 \\ 2-2-6x=n^2-1-2 \\ \cancel{2-2}-6x=n^2-1-2 \\ -6x=n^2-3 \end{gathered}[/tex][tex]\begin{gathered} \text{Divide both sides by }-6\text{ so that we could cancel out the coefficient of }-6\text{ on }x \\ -6x=n^2-3 \\ \frac{-6x}{-6}=\frac{n^2-3}{-6} \\ \frac{\cancel{-6}x}{\cancel{-6}}=\frac{n^2-3}{-6} \\ \\ x=\frac{n^2-3}{-6}\text{ (final answer)} \end{gathered}[/tex]