Question

Find the equation for thefollowing parabola.Vertex (-2,-4)Focus (-4,-4)A. (7-4)2 = -8(x-2)B. (x+4)2 = 8(yl)C. (y+4)2 = 8(x+2)D. (y+4)2 = -8(x+2)

Answer 1

The vertex of the parabola is of the form,

$(h,k)$

The vertex given is,

$(-2,-4)$

The general equation of parabola is

$(y-k)^2=4p(x-h)$

Here, p is the distance between vertex and focus.

$p=\sqrt[]{(-4-(-4))^2}+(-2-(-4)^{})^2$$p=\sqrt[]{4}$$p=2$

Susbtitute the values,

$(y+4)^2=8(x+2)$

The correct option is C.