Given:
The diameter of the semicircle is d= 2in.
The side of the square is a= 2in.
Required:
We need to find the perimeter of the given shape.
Explanation:
Recall that the perimeter of a two-dimensional figure is the distance covered around it.
The perimeter of the given shape is the sum of the length of arc of the semicircle and 3 sides of the square.
[tex]Recall\text{ that the length of the arc of the semicircle is }\pi r.[/tex]
The perimeter of the given shape is
[tex]P=\pi r+3a[/tex]
Consider the radius formula.
[tex]r=\frac{d}{2}[/tex]
Substitute d =2 in the formula
[tex]r=\frac{1}{1}=1\text{ in}[/tex][tex]Substitute\text{ }\pi=3.14,r=1\text{ and a=2 in the formula }P=\pi r+3a.[/tex][tex]P=3.14(1)+3(2)[/tex][tex]P=9.14in[/tex]
Final answer:
The perimeter of the given shape is 9.14in.
