Respuesta :

Since both fractions have the same denominator, you can simply add up (or substract) the numerators and keep the denominator unchanged :

x2+3x+2x2−16+3x+6x2−16=(x2+3x+2)+(3x+6)x2−16

=x2+6x+8x2−16.

Then, you can factorize it :

x2+6x+8x2−16=(x+2)(x+4)(x+4)(x−4)=x+2x−4.

In the case of a substraction :

x2+3x+2x2−163x+6x2−16=(x2+3x+2)(3x+6)x2−16

=x2−4x2−16=(x+2)(x−2)(x+4)(x−4).

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